I am going to show you guys, using math/physics, why gaining girth makes it necessary to use more force to achieve the same elongation. I hope this will settle the score on the subject of girth hindering length gains. I'd like to have some people chime in and have a good discussion about this.
No LaTeX support on these forums so this will look a little messy.
Average thickness of tunica albuginea = 1 mm
Penis #1 circumference = 101.6 mm (4")
cross-sectional area of tunica albuginea (assuming inner circumference of 100.6 mm) = 16.090564746 mm^2
Penis #2 circumference = 127 mm (5")
cross-sectional area of tunica albuginea (assuming inner circumference of 126 mm) = 20.133100289 mm^2
Penis #3 circumference = 152.4 mm (6")
cross-sectional area of tunica albuginea (assuming inner circumference of 151.4 mm) = 24.175635842 mm^2
Penis #1 length = 177.8 mm (7")
Penis #2 length = 177.8 mm (7")
Penis #3 length = 177.8 mm (7")
They have same length, but different circumference.
elastic modulus of tunica albuginea = 12 N/mm^2
(source = Expansion of the tunica albuginea during penile inflation in the nine-banded armadillo (Dasypus novemcinctus)
NOTE: You could pick any random value for the elastic modulus and the relationship between girth/force will still be linear. There are multiple sources which quote 12 MPa as the elastic modulus for the tunica albuginea, so I will be using that value just for fun.
elastic modulus = stress/strain
Stress = F/A where F = force applied (N) and A = cross-sectional area of material (mm^2)
Strain = E/L where E = desired elongation (mm) and L = original length (mm)
Using these definitions, it follows that
12 = (F/A) / (E/L)
Let's assume we want to elastically stretch the tunica 25.4 mm (1") more than it's starting length. All three penises have the same starting length.
12 = (F/A) / (25.4/177.8)
12 = (F/A) / 0.142857143
12 = F / (A*0.142857143)
Now let's calculate this for the three penises, plugging in the cross-sectional areas listed above:
Penis #1:
12 = F / (16.090564746 * 0.142857143)
12 = F / 2.298652109
F = 12*2.298652109
F = 27.583825308 N
This is equivalent to hanging 6.201 lbs
-------------------------------------------------
Penis #2:
12 = F / (20.133100289 * 0.142857143)
12 = F / 2.876157187
F = 12*2.876157187
F = 34.513886244 N
This is equivalent to hanging 7.75903 lbs
-------------------------------------------------
Penis #3:
12 = F / (24.175635842 * 0.142857143)
12 = F / 3.453662267
F = 12*3.453662267
F = 41.443947204 N
This is equivalent to hanging 9.317 lbs
Keep in mind that the hanging values I listed are only for fun in this hypothetical post and should not be used in real life to determine how much to hang, lol.
Here is a graph showing the force required (measured in N) to elastically elongate all 3 penises (from 0mm elongation to 100mm elongation). 100mm elongation won't actually happen in real life, I just let the values go that high so that it more clearly shows the difference between the forces required.
Left side = N (newtons)
Bottom = elongation in mm
Blue = 4" girth
Red = 5" girth
Green = 6" girth
girthlengthcorrelation-1.jpg
As you can see, there is only a slight difference initially, but as you elongate further, the gaps become wider.
No LaTeX support on these forums so this will look a little messy.
Average thickness of tunica albuginea = 1 mm
Penis #1 circumference = 101.6 mm (4")
cross-sectional area of tunica albuginea (assuming inner circumference of 100.6 mm) = 16.090564746 mm^2
Penis #2 circumference = 127 mm (5")
cross-sectional area of tunica albuginea (assuming inner circumference of 126 mm) = 20.133100289 mm^2
Penis #3 circumference = 152.4 mm (6")
cross-sectional area of tunica albuginea (assuming inner circumference of 151.4 mm) = 24.175635842 mm^2
Penis #1 length = 177.8 mm (7")
Penis #2 length = 177.8 mm (7")
Penis #3 length = 177.8 mm (7")
They have same length, but different circumference.
elastic modulus of tunica albuginea = 12 N/mm^2
(source = Expansion of the tunica albuginea during penile inflation in the nine-banded armadillo (Dasypus novemcinctus)
NOTE: You could pick any random value for the elastic modulus and the relationship between girth/force will still be linear. There are multiple sources which quote 12 MPa as the elastic modulus for the tunica albuginea, so I will be using that value just for fun.
elastic modulus = stress/strain
Stress = F/A where F = force applied (N) and A = cross-sectional area of material (mm^2)
Strain = E/L where E = desired elongation (mm) and L = original length (mm)
Using these definitions, it follows that
12 = (F/A) / (E/L)
Let's assume we want to elastically stretch the tunica 25.4 mm (1") more than it's starting length. All three penises have the same starting length.
12 = (F/A) / (25.4/177.8)
12 = (F/A) / 0.142857143
12 = F / (A*0.142857143)
Now let's calculate this for the three penises, plugging in the cross-sectional areas listed above:
Penis #1:
12 = F / (16.090564746 * 0.142857143)
12 = F / 2.298652109
F = 12*2.298652109
F = 27.583825308 N
This is equivalent to hanging 6.201 lbs
-------------------------------------------------
Penis #2:
12 = F / (20.133100289 * 0.142857143)
12 = F / 2.876157187
F = 12*2.876157187
F = 34.513886244 N
This is equivalent to hanging 7.75903 lbs
-------------------------------------------------
Penis #3:
12 = F / (24.175635842 * 0.142857143)
12 = F / 3.453662267
F = 12*3.453662267
F = 41.443947204 N
This is equivalent to hanging 9.317 lbs
Keep in mind that the hanging values I listed are only for fun in this hypothetical post and should not be used in real life to determine how much to hang, lol.
Here is a graph showing the force required (measured in N) to elastically elongate all 3 penises (from 0mm elongation to 100mm elongation). 100mm elongation won't actually happen in real life, I just let the values go that high so that it more clearly shows the difference between the forces required.
Left side = N (newtons)
Bottom = elongation in mm
Blue = 4" girth
Red = 5" girth
Green = 6" girth
girthlengthcorrelation-1.jpg
As you can see, there is only a slight difference initially, but as you elongate further, the gaps become wider.
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